Thursday, April 3, 2014

Latest oracle 1z0-803 exam dumps

Nowadays, even the most qualified IT professionals are not able to get good jobs due to the tough competition in this sector. Attaining a good job has also become difficult because of the rapidly changing technology. You need to keep your knowledge and technical skills up to date in order to survive in this competitive world. Obtaining an IT certification is a solution to this problem. IT sector is developing at a rapid pace and you can find lucrative jobs after acquiring IT certifications.
In order to cope up with the need of new certified IT professionals, some major international and domestic companies have started their educational and training programs providing various IT certifications. These certificate courses are intended to provide knowledge to the novices as well as the experienced IT professionals.
Test4actual provides the most comprehensive Implemenation 1Z0-803 study guide for our customers,We guarantee your success in the first attempt. If you do not pass the Middleware CertificationI “1Z0-803″ (Java SE 7 Programmer I) on your first attempt, send us the official result . Test4actual to every customer, we promise “If you failed the exam, give you full refund”. If you failed , You can send the score report to us.We will give you a FULLY REFUND of your purchasing fee OR send you another same value product for free. (For a full refund details)
Free 1Z0-803 Pdf Dumps Demo Download
1.Given:
public class x{
public static void main (string [] args){
String theString = “Hello World”;
System.out.println(theString.charAt(11));
}
}
What is the result?
A.There is no output
B.d is output
C.A StringIndexOutOfBoundsException is thrown at runtime
D.An ArrayIndexOutOfBoundsException is thrown at runtime
E.A NullPointException is thrown at runtime
F.A StringArrayIndexOutOfBoundsException is thrown at runtime
Answer: C
2.Given the code fragment:
String h1 = “Bob”;
String h2 = new String (“Bob”);
What is the best way to test that the values of h1 and h2 are the same?
A.if (h1 == h2)
B.if (h1.equals(h2))
C.if (h1 = = h2)
D.if (h1.same(h2))
Answer: B
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