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Oracle Oracle Database: SQL Fundamentals I 1z0-051
Exam Number/Code : 1z0-051
Exam Name : Oracle Database: SQL Fundamentals I
One year free update
Once failed,100% refund
Questions and Answers : 130Q&As
Update Time : 2013-12-26
Price :$79.00
Exam Number/Code : 1z0-051
Exam Name : Oracle Database: SQL Fundamentals I
One year free update
Once failed,100% refund
Questions and Answers : 130Q&As
Update Time : 2013-12-26
Price :$79.00
Free 1z0-051 Demo Download
1. View the E xhibit and examine the data in the EMPLOYEES table.
You want to generate a report showing the total compensation paid to each employee to date.
You issue the following query:
SQL>SELECT ename ‘ joined on ‘ hiredate
‘, the total compensation paid is ‘
TO_CHAR(ROUND(ROUND(SYSDATE-hiredate)/365) * sal + comm)
“COMPENSATION UNTIL DATE”
FROM employees;
What is the outcome?
A. It generates an error because the alias is not valid.
B. It executes successfully and gives the correct output.
C. It executes successfully but does not give the correct output.
D. It generates an error because the usage of the ROUND function in the expression is not valid.
E. It generates an error because the concatenation operator can be used to combine only two items.
Answer:C
1. View the E xhibit and examine the data in the EMPLOYEES table.
You want to generate a report showing the total compensation paid to each employee to date.
You issue the following query:
SQL>SELECT ename ‘ joined on ‘ hiredate
‘, the total compensation paid is ‘
TO_CHAR(ROUND(ROUND(SYSDATE-hiredate)/365) * sal + comm)
“COMPENSATION UNTIL DATE”
FROM employees;
What is the outcome?
A. It generates an error because the alias is not valid.
B. It executes successfully and gives the correct output.
C. It executes successfully but does not give the correct output.
D. It generates an error because the usage of the ROUND function in the expression is not valid.
E. It generates an error because the concatenation operator can be used to combine only two items.
Answer:C
2. Examine the structure of the PROMOTIONS table:
name Null Type
PROMO_ID NOT NULL NUMBER(6)
PROMO_NAME NOT NULL VARCHAR2(30)
PROMO_CATEGORY NOT NULL VARCHAR2(30)
PROMO_COST NOT NULL NUMBER(10,2)
The management wants to see a report of unique promotion costs in each promotion category.
Which query would achieve the required result?
A. SELECT DISTINCT promo_cost, promo_category FROM promotions;
B. SELECT promo_category, DISTINCT promo_cost FROM promotions;
C. SELECT DISTINCT promo_cost, DISTINCT promo_category FROM promotions;
D. SELECT DISTINCT promo_category, promo_cost FROM promotions ORDER BY 1;
Answer:D
name Null Type
PROMO_ID NOT NULL NUMBER(6)
PROMO_NAME NOT NULL VARCHAR2(30)
PROMO_CATEGORY NOT NULL VARCHAR2(30)
PROMO_COST NOT NULL NUMBER(10,2)
The management wants to see a report of unique promotion costs in each promotion category.
Which query would achieve the required result?
A. SELECT DISTINCT promo_cost, promo_category FROM promotions;
B. SELECT promo_category, DISTINCT promo_cost FROM promotions;
C. SELECT DISTINCT promo_cost, DISTINCT promo_category FROM promotions;
D. SELECT DISTINCT promo_category, promo_cost FROM promotions ORDER BY 1;
Answer:D
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